Practice Final Exam

t + 7   
t2 - 8t + 16
2t + 1   
t2 - 16   


Steps used to solve this problem:
  1. t + 7   
    t2 - 8t + 16
      ÷  
    2t + 1   
    t2 - 16   
  2. t + 7   
    t2 - 8t + 16
      ×  
    t2 - 16   
    2t + 1   
  3. t + 7   
    (t - 4)(t - 4)
      ×  
    (t + 4)(t - 4)   
    2t + 1   

  4. (t - 4) cancel since there is one in the denominator and one in the numerator
    5. t + 7   
    (t - 4)
      ×  
    (t + 4)   
    2t + 1   

  5. (t + 7)(t + 4)   
    (t - 4)(2t + 1)
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