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The half life of phosphorus-32 is 14.26 days. How much of the initial amount of 115 mg will be left in 4 days?

The formula is A = A₀1/2^t/h A is the final amount; A₀ is the initial amount;
       t = time; h = half life; The answer is A = 115(1/2)^4/14.26 = 94.6798 mg

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