# Inequalities

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- 4p > 8 → p > 8/4 → p > 2 This answer can also be written using the symbols (2, ∞)

The parenthesis means that the domain of p does not include 2 { ie p can only be a number larger than 2}

- 4r < 24 → r < 24/4 → r < 6 This can also be written using the symbols (-∞, 6)

The parenthesis means that the domain of r does not include 6 { ie r can only be a number smaller than 6}

- 4p ≥ 8 → p ≥ 8/4 → p ≥ 2 This can also be written using the symbols [2, ∞)

The bracket means that the domain of p does include 2 { ie p can be equal to 2 or any number larger than 2}

- 4r ≤ 24 → r ≤ 24/4 → r ≤ 6 This can also be written using the symbols ( -∞, 6]

The bracket means that the domain of r does include 6 { ie r can be equal to 6 or any number smaller than 6}

The best way to check that you have the correct answer is select a value and substitute it into

the original inequality. So for the last problem let us select r = 5 and substitute it into 4r ≤ 24 → 4(5) ≤ 24 → 20≤ 24 therefore the answer is correct.

Try these problems:

next absolute value inequalities

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