1. 7t³ + 14t² + 2t + 4  =   Group the first two terms together in parenthesis and then the last two terms
                                       together in parenthesis. Notice that the addition sign is between the two sets
                                       of parenthesises
   
   
2. (7t³ + 14t²) + (2t + 4)  =  
   
   
3. [(7t²t+ 7(2)t²)] + (2t + (2)2)  =  Factor each set of parenthesises.
   
   
4. 7t²(t + 2) + 2(t + 2) =   A common factor result from this procedure
                                        and that is (t + 2).
   
   
   
   
5. (t + 2)(7t² + 2) or (7t² + 2)(t + 2)   Is the final answer.

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