Practice Final Exam

p2 + 4p    2p2 + 16p + 32 p + 4    p2 - 16

Steps used to solve this problem:

p2 + 4p    2p2 + 16p + 32

÷

p + 4    p2 - 16

p2 + 4p    2p2 + 16p + 32

×

p2 - 16    p + 4

p(p + 4)    2(p + 4)(p + 4)

×

(p + 4)(p - 4)    p + 4



4. (p + 4) cancel since there is two in the denominator and two in the numerator

p    2(p + 4)

×

(p - 4)    1




p(p - 4)    2(p + 4)

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