Law of Sines

If angle 1 = 110 ⁰ angle 3 = 50⁰ and side A = 40.3 cm
What is the length of angle 3 and sides A and B

sin 500 40.3	=	sin 1100 B

B sin 50⁰ = 40.3 sin 110⁰

B = (40.3 sin 110⁰)/sin 50⁰

B ≈ 49.435 cm

angle 2 = 180⁰ - 110⁰ - 50⁰ = 30⁰

sin 500 40.3	=	sin 300 C

C sin 50⁰ = 40.3 sin 30⁰

C = (40.3 sin 30⁰)/sin 50⁰

C ≈ 26.304 cm


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